Math Β· Algebra & word problems
Inequalities and Solution Sets
Estimated time includes reading and one quiz. Take the time you need.
Start here: key ideas
- An inequality describes a set of values.
- Open endpoints exclude; closed endpoints include.
- Multiplying or dividing by a negative reverses order.
- Context determines whether whole-number answers make sense.
What youβll be able to do
- Solve and graph one-variable inequalities.
- Reverse the sign after negative multiplication or division.
- Interpret bounds in context.
Solve like an equation while protecting the order relationship.
Optional review
If youβd like to review the basics, visit Solving Linear Equations. You can start this lesson without completing those first.
A set rather than one answer
An inequality compares quantities with <, >, β€, or β₯. Its solution set includes every value making it true. The boundary separates solutions from nonsolutions. An open circle excludes the boundary; a closed circle includes it.
Greater than: endpoint excluded

Every value to the right of 3 satisfies x > 3, but 3 itself does not. This textbook uses a parenthesis for an excluded endpoint; an open circle means the same thing.
Greater than: endpoint excluded β OpenStax, via Mathematics LibreTexts. CC BY 4.0. Source image reproduced unchanged.
At least: endpoint included

For x β₯ 3, include 3 and every larger value. This textbook uses a square bracket; a filled circle is another common way to show that the endpoint is included.
At least: endpoint included β OpenStax, via Mathematics LibreTexts. CC BY 4.0. Source image reproduced unchanged.
Solve and protect order
Use balanced inverse operations as with equations. One special rule preserves order: multiplying or dividing both sides by a negative reverses the sign. For β3x>12, division by β3 gives x<β4. A compound inequality such as 2β€x<5 requires both comparisons: close 2, open 5, and shade between.
Interpret a bound
βAt most 40β means xβ€40; βat least 6β means xβ₯6; βmore than 10β means x>10. Context can restrict answers to whole counts. If $7 tickets must fit a $30 budget, 7tβ€30 means no more than 4 whole tickets.
Worked examples
Worked example 1: 5xβ7β€18. Add 7: 5xβ€25. Divide by 5: xβ€5. Close 5 and shade left.
Worked example 2: 8β2x>14. Subtract 8: β2x>6. Divide by β2 and reverse: x<β3. Testing β4 gives 16>14.
A reliable way to reason
The reversal rule follows from number-line order. Since 2<5, multiplying both values by β1 gives β2>β5: reflection across zero reverses left and right. Adding or subtracting does not reflect the line, so it does not reverse the symbol. Keep this cause in mind instead of flipping whenever a negative merely appears.
Graphing is also a verification method. For x>3, test 4; it works, so shade toward 4 and larger values. Test the boundary separately: 3>3 is false, so use an open circle. For xβ€β2, β2 itself works, requiring a closed circle, and β3 confirms shading left. Context may convert a numerical boundary into a usable count. If 6 notebooks must cost less than $25, 6n<25 gives n<25/6 dollars, but if n is a count instead of price, only whole-number values would be allowed. Always define the variable before deciding whether rounding or discrete interpretation is appropriate.
Guided reasoning and error checks
Worked context: A van can carry at most 1,200 pounds. Existing cargo weighs 375 pounds, and each crate weighs 55 pounds. If c is the number of additional crates, write 375+55cβ€1,200. Subtract 375 to get 55cβ€825; divide by positive 55 to get cβ€15. Because c counts crates, the feasible solutions are whole numbers from 0 through 15. Substitution confirms the boundary: 375+55(15)=1,200, so 15 is included.
Optional extension: solving a compound bound
For a compound bound, solve all parts together. From β4<2x+2β€10, subtract 2 throughout: β6<2xβ€8. Divide every part by positive 2: β3<xβ€4. The graph opens at β3, closes at 4, and shades between. Testing 0 confirms the interior.
Final self-check
When writing an answer from a graph, translate the endpoint and arrow separately. An open point at 2 with shading right means x>2; a closed point at 2 with shading left means xβ€2. Neither the circle nor the arrow alone is enough. Read both features, then test one shaded value and one unshaded value against the original inequality.
Terms to remember
- inequality
- A comparison using <, >, β€, or β₯.
- solution set
- All values that make an inequality true.
- boundary
- The endpoint separating solutions from nonsolutions.
- open circle
- A graph endpoint that is excluded.
- closed circle
- A graph endpoint that is included.
- compound inequality
- Two comparisons describing one set.
Your quick summary
- Isolate the variable with balanced operations.
- Reverse only after multiplying or dividing by a negative.
- Graph the endpoint and test the shaded side.
- Translate words such as βat mostβ and βat leastβ into inclusive bounds that fit the context.
Lesson quiz
Check what you learned, then review the explanations. This quiz saves results on this device only. Sign in to save quiz results to your account.